why would you want you quote the variable?

eval ("\$str = $str;");

should work.
at least no more parse error.


>   I keep getting this error when I use eval what am I missing
> Parse error: parse error in c:\httpd\doc\install.php(6) : eval()'d code on line 1
> $path="/home/sites/home";
> $fp3=fopen ("location.inc","w")or die("unable to open file (location.inc)");
> $str='include("$path/inc/dataconf.inc");';
> eval ("\$str = \"$str\";");
> fwrite($fp3,"$str \n"); 

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