Hi
Is this doing what you want, seems you have to use an array to create the
ref (just getting a handle on objects :)
<?
class test_class
{
var $dummy="nothing";
};
Function &assigning(&$returned,&$copy,&$object)
{
global $success;
$object->dummy="original";
$success=1;
$copy=$object;
$copy->dummy="copy";
$returned[] = &$object;
var_dump("In the function",$success,$returned[0],$copy,$object);
return $object;
}
$object = assigning($returned,$copy,new test_class);
echo "<br><br>";
var_dump("Out the function",$success,$returned[0],$copy,$object);
?>
At 03:06 PM 15/12/01, you wrote:
>Hello,
>
>I am trying to return a reference from an object created inside a
>function and at the same time have the object stored in a global
>variable.
>
>It seems that when I try doing it by assigning the object reference to a
>function argument that is passed by reference, nothing is returned in
>that variable despite inside the function the argument variable seems to
>have the right value.
>
>Is this a PHP bug or this is not the right way to do it?
>
>Try the example below.
>
>Manuel Lemos
>
><?
>class test_class
>{
> var $dummy="nothing";
>};
>
>Function not_assigning(&$not_returned,&$copy)
>{
> global $object;
>
> $object=new test_class;
> $object->dummy="original";
> $success=1;
> $not_returned= &$object;
> $copy=$object;
> $copy->dummy="copy";
> var_dump("In the function",$success,$not_returned,$copy,$object);
> return $success;
>}
>
>$success=not_assigning($not_returned,$copy);
>
>var_dump("Out the function",$success,$not_returned,$copy,$object);
>
>?>
>
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