>>Can anyone show me how to split() each line and parse to see if $user
exists?<<
// get contents of a file into a string
$filename = "./users.txt";
$fd = fopen ($filename, "r");
$contents = fread ($fd, filesize ($filename));
fclose ($fd);
// seperate the string into an array of lines
$linebreak = "\n";
$lines = explode($linebreak,$contents);
// seperate each line into an array of words
for ($i=0;$i<count($lines);$i++){
$words[$i]=explode(" ",$lines[$i]);
}
----- Original Message -----
From: "jtjohnston" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, December 20, 2001 10:59 PM
Subject: Re: [PHP] Beginner question?
Michael,
$fp = fopen ("./users.txt", "r");
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
Ok. But $buffer is not an array, is it? Why/what is 4096? What is !feof ?
Can anyone show me how to split() each line and parse to see if $user
exists?
Here's what I'm upto. I want to use users.txt as a user:password text
database
file.
I want to read users.txt into an array.
I want to parse each line splitting for ":"
user:pass
john:help
michael:thanks
$fp = fopen ("./users.txt", "r");
while (!feof ($fp)) {
$buffer = fgets($fp, 4096);
echo $buffer;
}
fclose($fp);
$user = "john";
$num_fields = count($buffer);
for ($i = 0; $i < $num_fields; $i++)
{
if ?? = $user then echo ??
}
Can anyone show me how to split() each line and parse to see if $user
exists?
> ><?php
> >$fp = fopen ("./info.txt", "r");
> >print $fp;
> >fclose($fp);
> >?>
> $fp is just a file pointer, not the actual contents of the file. You need
> to use fgets() (or something similar) to actually get the contents out.
> http://www.php.net/manual/en/function.fgets.php
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