"Bogdan Stancescu" <[EMAIL PROTECTED]> wrote in message
> 2. print $letter++ -- why doesn't this evaluate to "b" at the first loop
> it's already 'a'? Ok, this I may be able to explain because it's neither
> ++$letter" nor "print ($letter++)", but I wouldn't have trusted this
syntax to
> work this way a million years!

$foo++ is 'postfix', ++$foo is 'prefix' This means that the addition of 1
occurs AFTER (hence post) the expression's value is returned, not before.

In other words, it's equivalent to this:
print $foo;
$foo = $foo + 1;

not this:
$foo = $foo + 1;
print $foo;

-- Daniel Grace

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