[PHP] Re: how can I add a variable to this sample

[Tom Beidler]

So far nothing seems to work which leads me to believe there's something
else wrong.

Here's what I've tried

$service_type_insert = $x['926service_type']; //works fine when I hard code
a value in and returns proper value

$service_type_insert = $x[$$keyservice_type]; //returns empty even though I
know a value is there

$service_type_insert = $x['${key}service_type'];  //returns empty even
though I know a value is there

$service_type_insert = eval($x['$keyservice_type']);  //returns empty even
though I know a value is there. I added single quotes because without it
returned a parse error.


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