My way around this is using two fallback stages: for one you test
mysql_num_rows() after performing the query. If that's 0, use a default image
placed in the database beforehand. If that also returns a null mysql_num_rows()
then echo an image (probably the same default) from a known location in the



Rodrigo Peres wrote:

> Hi list,
> I have some images stored in a blob in mysql. I've made this code to output
> them to html, but the problem is if there's no image at a given id the page
> tooks a long time to load and display the "broken image", there's a way to
> avoid this, I mean, there's a way to print a message or another image if
> there's none in mysql ???

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