At 09:18 PM 1/10/2002 +0100, Ivo Stoykov wrote:
>How could I determine whether I have in the array's key integers *and*
>strings or integers only?
I'm not sure exactly what you're asking but I'll give it a shot...
>i.e.
>$a = new array('one', 'two', 'three'); // this has only integers (am I
>wrong?)
First of all, the "new" keyword assumes that you are instantiating an
object. For example if you created an object with the name foo you would
instantiate it like so:
$a = new foo;
So when creating arrays the "new" keyword is undesirable.
To address your question, yes your example above (after removing the "new"
keyword) will create an array named $a that has only integers for
keys. It's functionally the same as this:
$a = array(0 => 'one', 1 => 'two', 2 => 'three');
>$b = new array('one' => 'bla', 'two' => 'blabla', 'three' => 'blablabla');
>// integers & strings
The above example (again once corrected to remove the "new" keyword) will
create an array named $b that has ONLY strings for keys. There are no keys
that are integers because you didn't create any. You can test this by
trying to echo the values out by key:
echo $b['one']; //outputs "bla"
echo $b[0]; //outputs nothing because this key does not have a value.
This is perfectly legal:
$b = array ('one' => 'bla', 'two' => 'blabla', 'three' => 'blablabla', 0 =>
'blablablabla',
1 => 'blablablablabla');
In the above case you do have some keys that are strings and some that are
integers but they are DIFFERENT keys, representing DIFFERENT values.
Hope that answers your question...
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
