ooh... i dont know if i understood you correctly..but if i did, you simply
have to insert the location of the file in the users tupel like..

UserID    Name    Bla    Bla    picture
001         John       ...      ...      ./images/john.jpg

preferably i would only store the location when the user did upload an image
with an update query, so when fetching the information from your database,
you can check for empty location values... if you're working with mysql it
would be like...

while($my_array = mysql_fetch_array($result))
{
    echo "Stuff about the User";
    if($my_array[location])
    {
        echo "<img src=\"$my_array[location]\" width=\"100\"
height=\"100\">";
    } else echo "<img src=\"standard.jpg\">
}

but as i said, i dont know if i really understood your question.. (im
german, you know *g*)


----- Original Message -----
From: "Thomas Edison Jr." <[EMAIL PROTECTED]>
To: "Malte Fucks" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Sunday, January 20, 2002 6:26 PM
Subject: Re: [PHP] Upload & View Image : Database Thingy!!!!


> Malte,
>
> Thanks a lot. I was going through the File Upload
> Functions in the manual and i think that's what they
> were talking about too.
>
> Now there's just one thing. I can run the upload
> scripts and get the image for display too. But like i
> mentioned, this is for a PenPal system, a database
> based PenPal sysem.
> Basically there has to be some connection between the
> record entry by the user and the image. Which also be
> required when this record is displayed, for the
> corresponding image to be displayed. How migh that
> work?
>
> Thanks again,
> T. Edison jr.
>
> --- Malte Fucks <[EMAIL PROTECTED]> wrote:
> > I think the PHP image functions aren't what this guy
> > needs...
> >
> > First thing : File Uploads
> > You have to make a form, including an <input
> > type="file" name="yourfile">
> > tag, which refers to a php script like...
> >
> > <?
> > if($file)
> > {
> >    if(@copy($yourfile,"./$yourfile_name"))
> >    {
> >        echo "$yourfile_name was uploaded
> > succesfully";
> >    }
> >     else echo "ERROR - UPLOAD ABORTED";
> > }
> > ?>
> >
> > $yourfile_size includes the size of the file in
> > bytes, use an if-statement
> > to check if the picture-size fits your needs...
> > $yourfile_type includes... guess what... the file
> > type..
> > this should solve the upload problem...
> >
> > To control the size of an image is a matter of your
> > HTML... do something
> > like
> > <img src="yourimage" width="40px" height="40px">.
> > Its even possible to
> > insert height and width-values in percent...
> >
> >
> >
> >
> > --
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>
> =====
> Rahul S. Johari (Director)
> ******************************************
> Abraxas Technologies Inc.
> Homepage : http://www.abraxastech.com
> Email : [EMAIL PROTECTED]
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