${$vNames[1]} = "new value"; // look at variable-variables in the manual for more info
-----Original Message----- From: Gaylen Fraley [mailto:[EMAIL PROTECTED]] Sent: Sunday, January 20, 2002 3:44 PM To: [EMAIL PROTECTED] Subject: [PHP] Variable referencing/substitution How can this be done? If I have the name of a variable that is stored in an array, how do I use the stored value to represent the actual variable? Example: $variable = "old value"; $vNames[1] = '$variable'; //literal $variable I want to say $vNames[1] = "new value"; /and have $variable actually change. How? -- Gaylen [EMAIL PROTECTED] Home http://www.gaylenandmargie.com/ PHP KISGB v3.1 Guest Book http://www.gaylenandmargie.com/phpwebsite/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]