${$vNames[1]} = "new value"; // look at variable-variables in the manual
for more info
-----Original Message-----
From: Gaylen Fraley [mailto:[EMAIL PROTECTED]]
Sent: Sunday, January 20, 2002 3:44 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable referencing/substitution
How can this be done?
If I have the name of a variable that is stored in an array, how do I use
the stored value to represent the actual variable?
Example:
$variable = "old value";
$vNames[1] = '$variable'; //literal $variable
I want to say $vNames[1] = "new value"; /and have $variable actually
change.
How?
--
Gaylen
[EMAIL PROTECTED]
Home http://www.gaylenandmargie.com/
PHP KISGB v3.1 Guest Book http://www.gaylenandmargie.com/phpwebsite/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
