Basically I am setting ls > array(). I want each item to be an option in the array. I have have scoured for some time now and this is what I have come up with, but it is not populating each file as an <option>? The select box is just empty. I know this is an array because I have tested with print_r. Stuck!
Can someone tell me what I am doing wrong? ------------------------------------------------ <? $shell_scripts=`ls -1 /sm_scripts|grep -v backup|grep -v outmail|grep -v c_`; $shell_scripts=rtrim($shell_scripts); $arr1=split("\n", "$shell_scripts"); //print_r($arr1); echo "<p>"; echo "<select name=test>"; function generate_option_list($arr1, $set) { reset($arr1); while (list($key,$value) = each($arr1) ) { {$var.="<option value='$key'>$value</option>";} } return $var; } echo "</select>"; ------------------------------------------------ ?> TIA, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php