function foo($arg1_required, $arg2_optional="")
if ($arg2_optional=="") {
print "not passed";
}
else {
print "explicit";
}
}
-----Original Message-----
From: Rodent of Unusual Size [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 11, 2002 3:17 PM
To: [EMAIL PROTECTED]
Subject: [PHP] 'undef' as an argument value
An odd request.. I want to have optional function arguments
that *aren't* defined unless values are explicitly passed. Sorta
the equivalent of
function foo($arg1_required, $arg2_optional=undef)
if (isset($arg2_optional)) {
print "explicit";
}
else {
print "not passed";
}
}
Something like this is possible in Perl through the 'undef'
construct; is anything like this available in PHP?
--
#ken P-)}
Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/
Author, developer, opinionist http://Apache-Server.Com/
"Millennium hand and shrimp!"
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