"Andrey Hristov" <[EMAIL PROTECTED]> wrote in message
053801c1c9d0$5b4da400$0b01a8c0@ANDreY">news:053801c1c9d0$5b4da400$0b01a8c0@ANDreY...
> In PHP 4.0.5 and later, every parameter to str_replace() can be an
array.If search and
Thank you for pointing that out :)
I've now changed my code from the (rather lengthy) version to the following
which worked perfectly for me:
$regcheck = array("/","\\","^",".","[","]","$","(",")","*","?","{","}");
$regreplace =
array("","","\^","\.","\[","\]","\$","\(","\)","\*","\?","\{","\}");
$badwordtest = "/" . str_replace($regcheck,$regreplace,$badwords[$i]) .
"/i";
> BTW /abc/ and ~abc~ are equivalent regexes. So get a character which will
not occur in the string and put in the front and the end.
Does this mean that ~myword~ and /myword/ are identical?
I only used /myword/ because it's in the php manual example like that.
Cheers,
Rich
--
Fatal Design
http://www.fatal-design.com
Atari / DarkBASIC / Coding / Since 1995
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