Please take a look at the script below. If i want to show an image it doesnt work if it's under an if statement. Why in this case?
<? $feedb=0; if($feedb==0){ echo "<img scr='somepic.jpg'>";} echo "<img src='somepic.jpg'>"; ?> How can i solve this problem? thank you! Simon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php