Hi! > if(user($arbitraryVariable)==(1 or 2 or 3 or 4)) > What would be the proper syntax for this?
Here: if((user($arbitraryVariable) >= 1) and ($arbitraryVariable <= 4) and ($arbitraryVariable == round($arbitraryVariable))) In other cases, you'd have to write if((user($arbitraryVariable)==1) or (user($arbitraryVariable)==2) or (...)) Cheers, Kiko ----- It's not a bug, it's a feature. christoph starkmann mailto:[EMAIL PROTECTED] http://www.fh-augsburg.de/~kiko ICQ: 100601600 ----- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
