$query = "SELECT * from mytable";
$result = mysql_db_query("db", $query);

while ($myarray = mysql_fetch_array($result))
$title = $myarray[title];
echo "$title<br>";

Can someone PLEASE tell me why the coding above gives the following error:

Warning: Supplied argument is not a valid MySQL result resource in 
/var/web/somesite.com/html/index.php on line 5

It's absurd. It's driving me nuts. I'm about to introduce my computer to the 
pavement 40 feet below.

Thanks in advance for whoever sees what I am sure is a glaring and obvious 
flaw in the coding. I've been looking at it for an hours and just can't get 
anything from where I'm standing, maybe a different perpective will help.

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