Another thing you might want to try doing is throwing in phpinfo() somewhere to see what variables you are actually getting
-----Original Message----- From: Chuck Payne [mailto:[EMAIL PROTECTED]] Sent: Monday, March 18, 2002 1:44 PM To: Thalis A. Kalfigopoulos Cc: PHP General Subject: Re: [PHP] Brain Dead... When I go to post, I get the following alert...."Couldn't execute query" so I know I can connect, so it must be my SQL statement. That why I wondering how to pass the menu information to php so that it can do the SQL statement. I don't have $abc in the menu but I do have abc. So I am trying to find out how to do that. Maybe I am going about it the wrong way. Chuck ----- Original Message ----- From: "Thalis A. Kalfigopoulos" <[EMAIL PROTECTED]> To: "Chuck Payne" <[EMAIL PROTECTED]> Cc: "PHP General" <[EMAIL PROTECTED]> Sent: Sunday, March 17, 2002 9:40 PM Subject: Re: [PHP] Brain Dead... > What does "I get that it can't do the query" mean? What error are you getting? > > > On Sun, 17 Mar 2002, Chuck Payne wrote: > > > Ok, but I have this as an example.... > > > > <select name="abc" size="1"> > > <option value="a" selected>A</option> > > <option value="b">B</option> > > <option value="c">C</option> > > <option value="d">D</option> > > </select> > > > > Are you saying that abc should be $abc? I not clear. > > > > I have for my sql as this... > > > > db_name = "xxxinks"; > > > > $table_name = "ssslinks"; > > > > $connection = @mysql_connect("mybox.com","anyusers",!@#$%) or die ("Couldn't > > connect"); > > > > $db = @mysql_select_db($db_name, $connection) or die ("Couldn't select > > database."); > > > > $sql = "INSERT INTO $table_name > > (abc, key_word, links, name) > > VALUES > > ('$abc', '$keywords', '$links', '$name')"; > > > > $result = @mysql_query($sql, $connection) or die("Couldn't execute query."); > > > > but I get that it can't do the query. So I am think it not passing abc... > > > > Chuck > > ----- Original Message ----- > > From: "Thalis A. Kalfigopoulos" <[EMAIL PROTECTED]> > > To: "Chuck "PUP" Payne" <[EMAIL PROTECTED]> > > Cc: "PHP General" <[EMAIL PROTECTED]> > > Sent: Sunday, March 17, 2002 9:25 PM > > Subject: Re: [PHP] Brain Dead... > > > > > > > Dropdownmenu is a <select name="ddmenu"><option>....</select> > > > So the php variable that will hold the user's choice is stored in variable > > $ddmenu. > > > Thus, no "input" needed. > > > > > > > > > cheers, > > > --thalis > > > > > > > > > On Sun, 17 Mar 2002, Chuck "PUP" Payne wrote: > > > > > > > I am trying to get a form to work with pull down menu. But I am so brain > > > > dead I forgot how to get the input from the pull down menu. Where do I > > put > > > > input to pass on to php? > > > > > > > > Chuck Payne > > > > > > > > > > > > -- > > > > PHP General Mailing List (http://www.php.net/) > > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > > > > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
