if $img_url has a value, then I'd like to show the image, if it doesn't, then I'd like to show a message. What's wrong with my code? Am I incorrectly testing for the value? The else works fine, but not the if. Thanks!
if (!$img_url)
{
echo "<b>No Image URL Entered"</b><br>";
}
else
{
echo "<img src=\"$img_url\">";
}
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