if $img_url has a value, then I'd like to show the image, if it doesn't,
then I'd like to show a message.  What's wrong with my code?  Am I
incorrectly testing for the value?  The else works fine, but not the if.

        if (!$img_url)
        echo "<b>No Image URL Entered"</b><br>";
        echo "<img src=\"$img_url\">";

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