But to answer your question
The purpose of return, is to "return" a value..
function test($var)
{
return addslashes($var);
}
$foo = "Yes, I'am Very Awsome";
$foo = test($foo);
echo($foo);
// echo's, Yes I\'am Very Awsome
Understand?
----- Original Message -----
From: "Rasmus Lerdorf" <[EMAIL PROTECTED]>
To: "Gary" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Sunday, March 31, 2002 11:43 PM
Subject: Re: [PHP] return
> Nope, that code makes no sense. $_POST is an array containing the POST
> variables. You make a copy of that array an put it in $foo thereby
> overwriting the passed in $foo. Then you return $$foo which actually ends
> up returning a variable named $Array. It does not look like you have a
> $Array variable in scope, and it is surely not what the misguided coder
> behind this code was trying to achieve. In short, this is completely
> bogus.
>
> -Rasmus
>
> On Sun, 31 Mar 2002, Gary wrote:
>
> > Can someone explain to me the reason for using return.
> >
> > function _getValue($foo)
> > {
> > $foo = $_POST;
> > return ${$foo};
> > }
> >
> > TIA
> > Gary
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
