if the output of graph.php is a URL, your code should work.
<img src="/images/mypic.jpg">

if graph outputs the image itself, you have to do it a bit different:

in the html it should look like:

<img src="graph.php?...">

and graph.php should do something like:

header("Content-Type: image/gif");

echo $imagecontent;

Hope that helps


"Moschitz Martin" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
> What is wrong with the following statement? The Picture which is generated
> in graf.php is not displayed.
> echo "<img src=";
> include(" graf.php ");
> echo ">";
> thanxs
> martin

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