it is obvious, Scott:
> if ($sumItUp[$name] == "") {
is like to say "if $sumItUp[$name] is an empty string". Means, that if it
was not assigned, or if it contains any kind of character in it this will
result to false.
Try using this:
if(isset($sumItUp[$name]) and strlen($sumItUp[$name])) {
}
this will mean:
if there's such variable defined and the lenght of what it contains is
bigger than 0 the statement will result TRUE.
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
www.PHPBeginner.com
maxim@ phpbeginner.com
Scott Fletcher writes:
> Hi!
>
> I'm a little baffled on why the array is not working the way I expect it
> to. It showed there is something about the array I do not know about.
> Well, it's never too late to learn something new. So, here's the code and
> see if you can help me out.
>
> -- clip --
>
> $name = "TU4R";
>
> if ($sumItUp[$name] == "") {
> $sumItUp[$name] = 0;
> } else {
> //debug
> echo "**";
> $number = $sumItUp[$name];
> $number++;
> $sumItUp[$name] = $number;
> }
> echo $sumItUp[$name]."<br>";
>
> -- clip --
>
> In this case, the if statement never went into else statement when
> there's a number like 0, 1, 2, etc. So, what's the heck is happening here?
> When the array, "sumItUp[]" was empty then the number "0" was assigned and
> it work like a charm. So, when this code is repeated again, the if
> statement check the array, "sumItUp[]" and found a number, "0" and it is not
> equal to "" as shown in the if statement. So, therefore the else statement
> should be executed. But in this case, it never did. I tested it myself to
> make sure I wasn't missing something by putting in the php codes, "echo
> '**';" and the data, "**" was never spitted out on the webpage. So, it tell
> me that the else statment was never executed. So, the problem had to do
> with the data in the array itself. So, can anyone help me out? Thanks a
> million!!!!!!
>
> Scott
>
>
>
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