This works: <img src="<?php echo( "$image.gif" ) ?>" width=150 height=100 border=0>
This works too if you're not opposed to using straight php: <?php print "<html>\n<head>\n<title>Image Switch</title>\n"; print "<div align=center><img src=\"$image.gif\" width=150 height=100 border=0></div>\n"; print "</body>\n</html>"; ?> Later, Bob Weaver "Craig Westerman" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > I'm trying to set $image = imageA via a URL: > > http://www.abc123.com/php001/image_switch.php?image=imageA > > Script is: > > <html> > <head> > <title>Image Switch</title> > </head> > <body> > > <div align="center"><img src="<?php $image ?>.gif" width="150" height="100" > border="0"></div> > > </body> > </html> > > > Image link ends up as: > http://www.abc123.com/php001/.gif > > Link needs to be: > http://www.abc123.com/php001/imageA.gif > > What am I doing wrong? > > Thanks > > Craig ><> > [EMAIL PROTECTED] > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
