On Wednesday, April 17, 2002, at 03:59 PM, Robert Cummings wrote:
> Now if what you meant was the following: > > $objectFoo = new MyObject(); > $objectFee = &$objectFoo; > > unset( $objectFoo ); > > Then the object shouldn't be deleted since $objectFee is still > referencing > it. You will just break the reference. Correct me if I'm wrong *chuckle* What if I did $objectFoo = new MyObject; $objectFee = $objectFoo; unset($objectFoo); essentially, does PHP make a (deep|shallow) copy of an object in this reassignment, or is it just creating a new reference? Erik ---- Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
