On Wednesday, April 17, 2002, at 03:59  PM, Robert Cummings wrote:

> Now if what you meant was the following:
> $objectFoo = new MyObject();
> $objectFee = &$objectFoo;
> unset( $objectFoo );
> Then the object shouldn't be deleted since $objectFee is still 
> referencing
> it. You will just break the reference. Correct me if I'm wrong *chuckle*

What if I did

$objectFoo = new MyObject;
$objectFee = $objectFoo;


essentially, does PHP make a (deep|shallow) copy of an object in this 
reassignment, or is it just creating a new reference?



Erik Price
Web Developer Temp
Media Lab, H.H. Brown

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