It would seem the only way this could happen is if $last_name evaluates to true. Two suggestions:
1) Make some extra change in one of the printf statements so you can see which one is really being called. 2) If that doesn't illuminate anything, show a little more code. miguel On Sat, 11 May 2002, Jason Soza wrote: > Argh! > > I hate it when one little annoying thing starts up right when I think I have > the coding finished! I have the following code: > > if($last_name) { > printf("%s > %s's<br><b>%s</b><br>%s\n</td>",$first_name,$last_name,$year,$color); > } else { > printf("%s's<br><b>%s</b><br>%s\n</td>",$first_name,$year,$color); > } > > So if the person has a last name in the database, print "John Doe's 1990 > Red" and if they don't, print "John's 1990 Red". > > This is in a while() statement, and it works except that on one particular > query, the last record that comes up has a NULL value for the last name, but > rather than printing $first_name's it prints $first_name $last_name using > the last name of the previous record! > > Am I missing something there? Do I need to clear out a variable somewhere? > It seems like since $last_name isn't even called in the else statement, it > shouldn't even be showing up! > > Jason Soza > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php