I thought this is a secure way to find out if the file is a jpeg or not. So
you are suggesting to passit to the unix command file? How does that work.
Maybe you can make a small example or give a small hint on what to look for
on google. Sound interesting!

I tryed to to perform a createfromjpeg command to that file and it did not
work. So the magic is to save it in photoshop for web and then as jpeg and
not with save as (jpeg). But this gives me a headache, because how do user
know the difference? The file extension is jpeg and all programms can
display it. Maybe there is a way in php as well to do a kind of
createfromjpeg commmand?!

Thanx, Andy

"Miguel Cruz" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
> On Sun, 19 May 2002, andy wrote:
> > I do have trouble with finding out if a file is a jpeg or not.  This is
> > command I am using:
> >
> >  $_FILES[picture_location][type]
> >
> > works fine exept in one case: With Photoshop 6.0 I do open the jpeg
> > workes fine) an save as jpeg as another file name. Then upload the new
> > This returns a type called:
> >
> > application/octet-stream
> >
> > So what is this type anyway. I do know jpeg and jpg and pjpeg but
> > octed-stream?!
> application/octet-stream just means a generic binary file.
> I don't think that $_FILES[]['type'] is really all that useful for getting
> reliable information about a file, since it just trusts the browser/user,
> which could be uninformed, misinformed, or deliberately dishonest. Either
> pass the temp file to the unix 'file' command or peek inside it on your
> own (check the 'magic' file that comes with the unix 'file' command for
> details on what to look for).
> miguel

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