On Sat, May 18, 2002 at 12:38:37PM -0400, Gerard Samuel wrote:

> HTTP_ACCEPT_LANGUAGE is 'en-us, en;q=0.75, nl;q=0.50, fr;q=0.25'
> $foo = split(',', $_SERVER['HTTP_ACCEPT_LANGUAGE'] );
> foreach ($foo as $bar) {
>    $string = 
> preg_replace("/([a-z]{2})|(-[a-z]{2})|(;q=[0-9]\.[0-9]{2})/i", "$1", 
> trim($bar));
>    $array[] = $string;
> }

The replacements supposed to be \\1 rather than $1.  But, $1 might work
anyway.  Also, you can just assign the fuction to $array[], rather than
assigning it to $string and then $string to $array[].  But, even better,
use preg_match_all:

That'll eliminate the need to split() first.  Just put the stuff you 
want to keep, ie the two lettered language codes, in subpatterns "()" 
and keep the rest of the stuff out of sub patterns.



               PHP classes that make web design easier
        SQL Solution  |   Layout Solution   |  Form Solution  | |
 T H E   A N A L Y S I S   A N D   S O L U T I O N S   C O M P A N Y
 4015 7 Av #4AJ, Brooklyn NY     v: 718-854-0335     f: 718-854-0409

PHP General Mailing List (
To unsubscribe, visit:

Reply via email to