Gerard:
On Sat, May 18, 2002 at 12:38:37PM -0400, Gerard Samuel wrote:
> HTTP_ACCEPT_LANGUAGE is 'en-us, en;q=0.75, nl;q=0.50, fr;q=0.25'
>
> $foo = split(',', $_SERVER['HTTP_ACCEPT_LANGUAGE'] );
> foreach ($foo as $bar) {
> $string =
> preg_replace("/([a-z]{2})|(-[a-z]{2})|(;q=[0-9]\.[0-9]{2})/i", "$1",
> trim($bar));
> $array[] = $string;
> }
The replacements supposed to be \\1 rather than $1. But, $1 might work
anyway. Also, you can just assign the fuction to $array[], rather than
assigning it to $string and then $string to $array[]. But, even better,
use preg_match_all:
http://www.php.net/manual/en/function.preg-match-all.php
That'll eliminate the need to split() first. Just put the stuff you
want to keep, ie the two lettered language codes, in subpatterns "()"
and keep the rest of the stuff out of sub patterns.
Enjoy,
--Dan
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