but the scriptname itself will be included there.
Try this, if you don't want the scriptname to be included.:
$url = preg_replace('/^(http:\/\/)[^\/]+((\/[^\/])*\/)([^\/]+)$/',
'\\1$SERVER_NAME\\2', $SCRIPT_URI);
Haven't tested them, but should work.
Michael
"Michael Virnstein" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> typo:
>
> $url = preg_replace('/^(http:\/\/)[^\/]+(\/.*)$/', '\\1$SERVER_NAME\\2',
> $SCRIPT_URI);
>
> Michael
>
> "Michael Virnstein" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > try:
> >
> > $url = preg_replace('/^(http:\/\/)[^\/]+(\/.*)$, '\\1$SERVER_NAME\\2',
> > $SCRIPT_URI);
> >
> > Michael
> >
> > "Jtjohnston" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > I want to detect the url my .php lies in.
> > >
> > > This is over kill and BS:
> > >
> > > $myurlvar = "http://".$SERVER_NAME.parse($SCRIPT_NAME);
> > >
> > > How do I get "http://foo.com/dir1/dir2/dir3/";.
> > >
> > > There seems to be nothing in phpinfo() that will give me a full url to
> > > play with.
> > >
> > > Flame me if you will, but I browsed TFM and found nothing
inspirational.
> > >
> > > Looked at phpinfo() too and got discouraged.
> > >
> > > I need a full url.
> > >
> > > John
> > >
> > >
> >
> >
>
>
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