Well what exactly are you trying to do? You can't name an index of an array the same thing and expect different values....
ed At 03:36 PM 5/30/2002 +0200, Victor Spång Arthursson wrote: >Hi! > >I want to create an array that looks like follows: > >$array["untitled_1.jpg"][] = 0 >$array["untitled_1.jpg"][] = 3 >$array["untitled_1.jpg"][] = 4 >$array["untitled_2.jpg"][] = 0 >$array["untitled_3.jpg"][] = 1 > >What I'm thinking about is accessing all "untitled_1.jpg" values by doing >the following: > >$newarray = $array["untitled_1.jpg"]; > >and receive an array with 3 indexes which has the values 0,3,4... > >This doesn't works... > >$array["untitled_1.jpg"][] = 3 seems to overwrite >$array["untitled_1.jpg"][] = 0 and then $array["untitled_1.jpg"][] = 4 >overwrites $array["untitled_1.jpg"][] = 3... > >How should I solve this? > >Sincerely > >Victor > > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
