On Mon, 2002-06-03 at 12:45, Jared Boelens wrote:
> So am i to understand that i will have to do it in this manner?


No no no... B extends A, and you have an instance of B. Just do this:

class A
        var $b;

class B
        function B($b)
                $this->b = $b;

That will work fine.



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