I am having hard time passing the variable to the next page. May be you
can help me. Let me explain:


I am using mySQL database to store information about images (ID, name,
author, description, etc).  I am pulling some of the information to
create this (look at the example here:
http://www.gibsonusa.com/test/page/index.php) Now, I want a new window
appear when user clicks on the image. I have achieved it with the
following script: 


echo "<script language=\"JavaScript\">";

echo" function pop1() {";

echo" window.open(\"info.php?prod_id=$result[0]\"); }";   \\ $result[0]
is variable that stores id of the image in database

echo "</script>";


I am calling this function in the following manner: echo"<img


You can see the result if you click on the image.  The new page opens
up, BUT the id (product_id in this case) value is not passed to the next
page correctly.  If you click on the first or second image on the first
page it shows that the ID is the same for both of them.  However if you
look at the source code you can see that the ids are assigned correctly.
The same thing happens if you click on any image that says "no image
available" (I am using different script to generate those).  It seems
that the script picks up and stores in the memory the value of an ID of
the last image generated with the script (I don't know if that make


Oh, by the way the contents of info.php that I am calling in the script
above are as following:


$myid = $_GET['prod_id'];

echo" Product ID: $myid<br>";



What am I doing wrong?  Can you help?


Thank you. 

Sorry for lengthy e-mail.


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