Try...
<?
//$dirname should contain the directory name including it's full path...
$handle=opendir($dirname);
while ($file = readdir($handle)){
echo("$file is located in the $dirname directory");
}
?>
HTH,
Dw.
Sqlcoders.com Dynamic data driven web solutions
----- Original Message -----
From: "Steven Mallett" <[EMAIL PROTECTED]>
To: "php-general" <[EMAIL PROTECTED]>
Sent: June 08 2002 07:23 AM
Subject: [PHP] Reading from a dir.
> Is there another way to read the files from a directory?
>
> I tried the following:
>
> foreach (glob("*.txt") as $filename) {
> echo "$filename size " . filesize($filename) . "\n";
> }
>
> but get an error whether safe mode is on or off.
>
> I'm just learning as you might guess.
>
> --
> Steve Mallett http://OSDir.com - Stable, Open Source Apps
> [EMAIL PROTECTED] | [EMAIL PROTECTED]
> http://open5ource.net <personal> | With new, all powerful, blogging
> action!
>
>
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>
>
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