Can simply set $i before the while.
I assume the $last_name is coming from the DB.
Not exactly sure what you want, but hope this helps.
good luck... Dan.
----------------------
$i
= 0;
while ($row = mysql_fetch_array($result)) {
extract($row);
if (($i % 5) == 0) print "<tr>\n";
$i++;
@$last_name .= '';
if($last_name <> '')
<print stuff here>
else
<print other stuff>
...
if (($i % 5) == 0) print "</tr>\n";
}
Jason Soza wrote:
> I'm just curious if there's a way to restructure my code so as to avoid
> getting "Undefined Variable" errors. I keep getting them and I know they're
> nothing to worry about for the most part, I'd like to get rid of them
> without turning off error reporting if possible. In the following code, I
> get an undefined variable error for $i and for $last_name, is there anything
> I can do to actually define them? $last_name is a variable produced by my
> MySQL query, $i is just a counter:
>
> while ($row = mysql_fetch_array($result)) {
> extract($row);
> $i++;
> if($i=="1") {
> print "<tr>\n";
> }
>
> if($last_name) {
> <print stuff here>
> } else {
> <print other stuff>
> }
> ...
> if ($i=="5") {
> print "</tr>\n";
> $i=0;
> }
> }
>
> Thanks!
>
> Jason Soza
>
>
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