On Saturday, June 29, 2002 at 10:03:16 PM, Chase wrote:
> I am *very* new to PHP, so this may seem like a stupid question...  I am
> trying to generate dynamic drop-down lists for use in an HTML form, but 
> I have done something wrong with my code.  Instead of getting one list 
> box with three options, I am getting three list boxes with one option. 
> I have included this piece of my code...  Can anyone help???

Yes, you have the select open and close tags inside the loop. Move them either
side as follows...

$link = mysql_connect("localhost", "user", "pass");
mysql_select_db("my_db", $link);

$result = mysql_query("SELECT SKU, Description, Retail FROM linecard
WHERE sku=61 or sku=239 or sku=318", $link);
$num_rows = mysql_num_rows($result);

if($num_rows) {
        print("<select name=\"test\">");
        while($row = mysql_fetch_row($result))

           print("<option value=\"$row[0]-$row[1]-$row[2]\">$row[1] -


      } else {
        print("<option value=\"\">No Parts Created Yet</option>");


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