On Saturday, June 29, 2002 at 10:03:16 PM, Chase wrote:
> I am *very* new to PHP, so this may seem like a stupid question... I am
> trying to generate dynamic drop-down lists for use in an HTML form, but
> I have done something wrong with my code. Instead of getting one list
> box with three options, I am getting three list boxes with one option.
> I have included this piece of my code... Can anyone help???
Yes, you have the select open and close tags inside the loop. Move them either
side as follows...
<?
$link = mysql_connect("localhost", "user", "pass");
mysql_select_db("my_db", $link);
$result = mysql_query("SELECT SKU, Description, Retail FROM linecard
WHERE sku=61 or sku=239 or sku=318", $link);
$num_rows = mysql_num_rows($result);
if($num_rows) {
print("<select name=\"test\">");
while($row = mysql_fetch_row($result))
{
print("<option value=\"$row[0]-$row[1]-$row[2]\">$row[1] -
\$$row[2]</option><br>");
}
print("</select>");
} else {
print("<option value=\"\">No Parts Created Yet</option>");
}
?>
--
Stuart
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