On Fri, 5 Jul 2002, Kelly Meeks wrote:
> If I had this information stored in a database field, 
> <img src="<? echo $content_output["site_logo"]; ?>">
> 
> how could I assign it to a variable and output it?

I'm not sure that you can eval() HTML.

Perhaps if your cell contained:

   echo "<img src='{$content_output['site_logo']}'>"

you would have better luck. Don't quote me on it though.

miguel


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to