On Fri, 5 Jul 2002, Kelly Meeks wrote: > If I had this information stored in a database field, > <img src="<? echo $content_output["site_logo"]; ?>"> > > how could I assign it to a variable and output it?
I'm not sure that you can eval() HTML. Perhaps if your cell contained: echo "<img src='{$content_output['site_logo']}'>" you would have better luck. Don't quote me on it though. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php