imagejpeg($thumbnail,'test.jpg',$quality); should of course be imagejpeg($thumbnail,'',$quality);
Otherwise you are creating a new image on your server and not outputting it to the browser. /Joakim > -----Original Message----- > From: Mark Colvin [mailto:[EMAIL PROTECTED]] > Sent: Tuesday, July 09, 2002 12:30 PM > To: [EMAIL PROTECTED] > Cc: Php (E-mail) > Subject: RE: [PHP] PHP Image Functions > > > Thanks for your reply. Its a bit further forward but still > not working. I > have split the files and the output now shows the text part of 'img > alt="text" src="...' ie it won't recognise the image. > Anything else you can > think of? > > > > **************************************************** > This e-mail is intended for the recipient only and > may contain confidential information. If you are > not the intended recipient then you should reply > to the sender and take no further ation based > upon the content of the message. > Internet e-mails are not necessarily secure and > CCM Limited does not accept any responsibility > for changes made to this message. > Although checks have been made to ensure this > message and any attchments are free from viruses > the recipient should ensure that this is the case. > **************************************************** > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
