Well, if you're just going to show your image (no resizing or other image operations) you don't need to use gd at all. You could just change the Content-Type and print.
<snippet> header("Content-Type: $mimetype"); print($imagedata); </snippet> /lasso ([EMAIL PROTECTED]) Tommi Trinkaus wrote: > Hi, > > i stored some jpegs in an mysql-database (one field for data, one for type) > and i'm able to download them and to show them in an <img> tag. > But wat i want is to use the stored data to create a thumbnail to show it > within the browser without creating a file - how can i pass the mysql-blob > directly to a gd-function like imagecreate() or imagejpg() ?? (gd-library is > working well) > > thank you for any answer, tommi > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php