>The script was working great before PHP 4.2.x and not after that. So, I
>looked through the code and came upon this variable, "$$var". I have no
>idea what the purpose of the double "$" is for a variable. Anyone know?
> $var = "v".$counter."_high_indiv";
> $val3 = $$var;
Read the manual about "variable variables"
basically, they are creating a variable name like 'v1_high_indiv' (in $var)
and then when they say $$var they really mean $v1_high_indiv
It's probably not the source of your problem.
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