On 25 Jul 2002 at 2:04, GOLD, MATTHEW wrote:
> thank you very much for your quick response.
>
> How do I run mysql_fetch_row before the while loop? I don't want two
> loops, because I just want this variable to print out once.
>
> I tried this, but it didn't work:
>
> $query = "Select blah1, blah2, blah3 from blahtable";
> $result = mysql_query ($query)
> or die ("Cannot complete query");
>
> $row = mysql_fetch_row ($result))
> print ("$row[4]");
>
> while ($row = mysql_fetch_row ($result))
> {
> print "$row[1], $row[2], etc.");
> }
>
> ?>
>
> I realize that my problem is that I don't really understand arrays...but I
> am new to all of this, and I very much appreciate your help.
>
> best,
>
> Matt
Not sure if I responded to this, so ....
$query = "Select blah1, blah2, blah3 from blahtable";
$result = mysql_query ($query) or die ("Error: ". $mysql_error() )
//mysql_error gives you a useful error message!
// or die ("Cannot complete query");
$row = mysql_fetch_row ($result))
print ("$row[4]");
mysql_data_seek($result, 0); //Reset pointer to first record
while ($row = mysql_fetch_row ($result))
{
print "$row[1], $row[2], etc.");
}
?>
You might want to look at extract as well.
Cheers
--
David Robley
Temporary Kiwi!
Quod subigo farinam
"This is mutiny!" said Tom bountifully.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
