Thank you, I figured it out 30 seconds after I posted the question, you
were right about the problem.

- Victor >

-----Original Message-----
From: Chris Wesley [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 4:11 PM
To: 'PHP'
Cc: Victor
Subject: Re: [PHP] help, array values echoed as Array on loop!

On Mon, 2 Sep 2002, Victor wrote:

> $ID_arr[] = explode(',', $pictures); # make db data into array
> This is the string:
> 15,16,17,18,19
> why does it echo as Array?

... because you've created an array ($ID_arr) with an array as the first
value (the result of the call to explode()).  Take the brackets off
$ID_arr, and you'll get what you want.  You don't want your array in an
array ... you just want an array.

$ID_arr = explode(',', $pictures);

If you really wanted your array in the array, then loop over $ID_arr[0].
(I doubt that's what you were going for, though.)


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