Hello Kevin,
Yes, and that's the good part. The bad part is that $a is affected (try
print_r($a)). I don't think it should be.
Michiel
At 12:41 PM 9/20/2002, Kevin Stone wrote:
>Worked fine for me..
><?phpecho "<pre>";print_r($r);echo "</pre>";?>-----------Array
>(
> [k] => Array
> (
> [0] => a1
> [1] => b1
> )
>
>)
>-----------Access the merged array with with $r['k']; with values at
>$r['k'][0] and $r['k'][1]. Is this not what you wanted?
>-Kevin
>
>----- Original Message -----
>From: "Michiel van Wessem" <[EMAIL PROTECTED]>
>To: <[EMAIL PROTECTED]>
>Sent: Friday, September 20, 2002 10:14 AM
>Subject: [PHP] array_merge_recursive
>
>
> > Hello!
> >
> > I'm fairly new to PHP and absolutely new to this mailing list.
> >
> > I subscribed and I'm writing because I observed some strange behavior with
> > array_merge_recursive(). I'm using PHP version 4.1.2. Please look at the
> > following code:
> >
> > $a = array('k' => array('a1'));
> > $b = array('k' => array('b1'));
> > $r = array_merge_recursive($a, $b);
> > echo count($a['k']), '<br>';
> > echo count($b['k']), '<br>';
> >
> > This will print
> > 2
> > 1
> >
> > Apparently $a['k'] has been merged with $b['k'] and $a['k'] has been set
>to
> > the resulting two-element array. I did not expect this behavior: I
>expected
> > the function to make a new array, which contains both 'a1' and 'b1'. Only
> > $r['k'] should refer to this new array.
> >
> > Otherwise, in my opinion, array_merge_recursive should not return a value,
> > just modify the first argument.
> >
> > Should I file a bug report about this?
> >
> > Thank you,
> >
> > Michiel van Wessem
> >
> >
> > Network Administrator
> >
> >
>
>
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