>> I am new to php and that the folowing error: Warning:
>> supplied argument is not a valid MySQL result resource in 
>> /home/tbonestu/public_html/smallimages.php
>> i dont know what i am doing wrong here is the code:
>>  @ $db = mysql_pconnect(connect info);
>>  mysql_select_db("images");
>>  $query = "select * from images where type =".$type."";  $result = 
>> mysql_query($query);  $num_results = mysql_num_rows($result);

>That generally means your query failed. Try to echo mysql_error() after
your query to see what the problem is. You probably need quotes around $type
or $type has no value.

You also have too many quotes on the $query line, try echoing your $query
variable to see if it reads properly.


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