# Re: [PHP] How do i assign Integers only and not real numbers?

```If you end up using floor(), watch for floating point errors. You could
expect your division to come out to a whole number, say 12, but be
represented by 11.99999999999 in the computer. So that'll floor() to 11. You
can add a fluff to your division to counteract this:```
```
\$years = floor(\$years + (\$themonth / 12) + 0.0001);

---John Holmes...

----- Original Message -----
From: "Support @ Fourthrealm.com" <[EMAIL PROTECTED]>
To: "Tom" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, September 23, 2002 11:06 AM
Subject: Re: [PHP] How do i assign Integers only and not real numbers?

> Hi Tom,
> Try this:
> \$years = round(\$years + ( \$themonth / 12 ));
>
>
>  From the manual:
> float round ( float val [, int precision])
> Returns the rounded value of val to specified precision (number of digits
> after the decimal point). precision can also be negative or zero
(default).
>
>
> ceil() and floor() also exist.
>
>
>
> Peter
>
>
> At 03:46 PM 9/23/2002 +0100, Tom wrote:
> >Hi all,
> >
> >I have a line of code that assigns a new year number: -
> >
> >\$years = \$years + ( \$themonth / 12 );
> >
> >but sometimes \$years == 1998.0833333333
> >
> >or
> >
> >\$year == 2002.75
> >
> >etc...
> >
> >I cant find anything like a round() or floor() function in PHP so that
year
> >would be 1998 or 2002 only.
> >
> >Does anyone know what function would do this?  Sorry if I`m wasting your
> >time if its a really obvious one!
> >
> >thanks in advance,
> >Tom
> >
> >
> >
> >--
> >PHP General Mailing List (http://www.php.net/)
> >To unsubscribe, visit: http://www.php.net/unsub.php
>
> - - - - - - - - - - - - - - - - - - - - -
> Fourth Realm Solutions
> [EMAIL PROTECTED]
> http://www.fourthrealm.com
> Tel: 519-739-1652
> - - - - - - - - - - - - - - - - - - - - -

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

```