You can use this code: print <<< EndOfHTML
put all html in here even with " EndOfHTML; This will print out all html. and dont care about special signs. goodluck. Martin "Reuben D. Budiardja" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi all, When using Apache web server, with php module, I can intermix between HTML code and PHP. But when using PHP as CGI (in other web server, eg. OMNI), as far as I know, I have to write all HTML code using either echo or print statement, right? Is there a better way to do this? The problem is that someone already have the HTML part, and I just wont to insert some PHP codes around it. If I use echo " [HTML CODE] "; then I have to escape all the quotation mark (") inside the HTML code, which is laborious and not really elegant. The same problem occurs even if I use echo with single quote instead of double quote. I have to escape all the single quote, since the HTML code is also intermix between HTML and javascript, which has single and double quotes. How do I best solve this problem? Thanks a lot for any response. Reuben D. Budiardja -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
