>errors, but it doesnt do what i want it to do - instead of returning any
>three digit combo that doesnt return 222, it just prints EVERY combo whice
>passes my conditional statement to weed out numbers that have digits where 2
>or more are the same.
I can't write bug-free code first time either. I have had to learn to 
debug. In this case I would start just before your line...

>if ($answer != 222) {
...and put in "echo $answer" to see what number it actually has.


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