Your code makes no sense and the error message is telling you exactly what
you did wrong. opendir() returns a directory handle to be passed to
readdir(). Calling chdir() on a directory handle makes no sense. You
want to chdir to the same string that you passed to opendir()
-Rasmus
On Wed, 2 Oct 2002, Nokar wrote:
> I get this error from php when i execute this code can you help me ;)
> Warning: chdir() expects parameter 1 to be string, resource given in
> C:\xxxx\read.php on line 146
>
> 145 echo "<center>Attachment :";
> 146 $rep = opendir("C:\\xxx\\Attach\\$id\\");
> 147 chdir($rep);
> 148 while ($zone = readdir($rep))
> 149 {
> 150 if (!is_dir($zone)) echo "<a
> href=\"../Attach/$id/$zone\">$zone</a><br>";
> 151 }
> 152 echo "</center>";
> 153 }
>
>
>
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