Lallous wrote: > John, what you said would simply produce: > var x = ['str1,str2,str3'] > and not as I want: > var x = ['str1','str2','str3']
Elias,
did you actually tried that? Because it does produce what you want...
<?
$x = Array( 'str1', 'str2', 'str3' );
echo sprintf("x=['%s']", join("','", $x));
?>
produces:
x=['str1','str2','str3']
Grtz Erwin
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