hi there
youre missing a return.
here is the code i use in order to supress the submission of the form in
case the field validation (or the "are you sure... ?" confirm()) returns
false:
< form onSubmit="return validateForm(this)">
Have fun,
Holger
----- Original Message -----
From: "Davy Obdam" <[EMAIL PROTECTED]>
To: "PHP Mailinglist" <[EMAIL PROTECTED]>; "PHP-WIN Mailinglist"
<[EMAIL PROTECTED]>
Sent: Wednesday, October 09, 2002 4:17 PM
Subject: [PHP] confirm box
> Hi people,
>
> Maybe a bit off-topic, but i thought lets ask anyway. I have a guestbook
> admin page were i can delete multiple items from the database using
> checkboxes. So when i click on the Submit button i would like a
> javascript confirm box coming up. I have done that, but it deletes the
> item(s) anyway, also if i click on cancel.
>
> This is my javascript code in the head of the document:
>
> <script language="JavaScript" type="text/javascript">
> <!--
> function ConfirmDelete()
> {
> input_box=confirm("Are you sure that you want to delete the
> selected items?");
> if (input_box!=true)
> {
> return false;
> }
> else
> {
> return true;
> }
> }
> //-->
> </script>
>
> This is what i use in my PHP code:
>
> <?php
> //Guestbook admin page
> echo "
> <form name=\"admin\" onSubmit=\"ConfirmDelete();\">";
> //The rest of my form
> echo "
> <input type=\"submit\" name=\"submit\" value=\"delete\">
> </form>";
> ?>
>
> <?php
> //Delete items from guestbook
> if(isSet($submit))
> {
> //Delete items
> }
> ?>
>
> Any help is appreciated, thanks for your time,
>
> Best regards,
>
> Davy Obdam,
> mailto:[EMAIL PROTECTED]
>
>
>
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