No. That will not work. Include does not return the text to a variable. Please read the manual page on include. You have to use file, fopen, or include() _with_ output buffering in order for this to work.
---John Holmes... > -----Original Message----- > From: CJ [mailto:[EMAIL PROTECTED]] > Sent: Saturday, October 12, 2002 3:09 PM > To: [EMAIL PROTECTED] > Subject: [PHP] Re: $html_code .= include ("filetoinclude.txt"); > > > $html_code = $html_code.include("filetoinclude.txt"); > > > Research And Development wrote: > > Should this work? > > > > $html_code .= include ("filetoinclude.txt"); > > > > I am populating a variable with html to be printred later as usual: > > $html_code .= "html....". > > > > But I have some static html files that I want included in the html that > > I am storing in the variable. The HTML is in text files. The above code > > obviously does not work. I want to know if there is another way. > > > > Thanks. > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
