Ok, let me see if I have this right:
When you do:
$var = new myClass();
$var instantiates and holds a copy of myClass. But when
$var =& new myClass();
$var instantiates and references that instantiation?
If so, then I'm curious - if you do:
$var2 =& new myClass();
and you modify the member variables in $var2, will the
member variables of $var be modified as well? Or does
$var2 reference a seperate instantiation?
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