Your get statement is wrong: http://maloyportalen.no/~critical/maloy/index.php?page=main2.php?id=7 use http://maloyportalen.no/~critical/maloy/index.php?page=main2.php&id=7
You only get 1 question mark, any after will be treated as part of the variable page. Hi! I started to learn PHP yesterday, and I have just entered a little problem. In my index.php file. I have this line: <? if ($page== '') { $page="main.php" ; } else { $page=$page.""; } include ($page); ?> wich controles the main page locaton, just like frames. It makes the files appear in the middle of the site. Now over to the problem: I am making a newsscript with PHP and PostgreSQL. I have now gotten PHP to extract the news from the database. I am using numbers as ID for each post. 1, 2 ,3, 4, 5, 6 and so on. I use them to make a READ MORE link on the news posts. I am calling my "READ MORE"-page for main2.php, this contains PHP code that finds the story thats connected to the given number. and I use this to make it appear: <a href="main2.php?id=row['id']> sort of speak.. The problem: This link gives me the story: http://maloyportalen.no/~critical/maloy/main2.php?id=7 But that makes it go on a seperate page. And this link does not work at all: http://maloyportalen.no/~critical/maloy/index.php?page=main2.php?id=7 It returns this error: Warning: Failed opening 'main2.php?id=7' for inclusion (include_path='.:/usr/share/pear') in /home/critical/public_html/maloy/index.php on line 21 Line 21 is the following: <? if ($page== '') { $page="main.php" ; } else { $page=$page.""; } include ($page); ?> How can I write it so I can use: http://maloyportalen.no/~critical/maloy/index.php?page=main2.php?id=7 Regards Paul Ottar Tornes. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php