The syntax as I have used it is (not the cleanest or best way to do
it by a long run - but it works):

if ($_POST['shipper_save'] == "off") {
  $shipper_save = "";
else {
  $shipper_save = "checked";
<input type="checkbox" name="shipper_save" <?=$shipper_save?>>

this will have the checkbox be checked by default, also you can do what
ever other things you need to do based on the on/off conditions.

On Fri, 1 Nov 2002 10:47:43 -0500
"DonPro" <[EMAIL PROTECTED]> wrote:

> Hi,
> I have a form with a checkbox like so:
> <input type="checkbox" value="ON" name="shipper_save">
> When I submit, the value is always shown as "ON" regardless of whether
> I've checked the checkbox or not.  So this begets the question, How
> can I code my PHP form processing script to determine whether the
> checkbox was checked?
> Thanks,
> Don
> -- 
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Tom Woody
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  fax: 214-631-0800

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